The sum of the digits of a two digit number is 11. If the digits are reversed, the new number is 27 less than the original number. Find the original number. Solution
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Answer:
Step-by-step explanation:
let the ten's digit be x and one's digit be y
by given condition ,
x+y=11________1
10y+x =10x+y- 27
= 9y-9x= -27
= 9(y-x)=-27
= y-x=-3_______2
adding 1 and 2
(x+y)+(y-x)=11+-3
2y = 8
y= 4
put y=7 in equation 1,
x+4=11
x=11-4
x=7
the original number = 10x+y
= 10(7)+4= 74
ravgersid555:
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answer is 27.... answer is 27
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