Question

The sum of the digits of a two digit number is 11.If the digit at the unit place be y. Write the two digit number 

1) 11X 10 + y

2) 10 x y + y

3) 10 y + (11- y)

4) 10(11- y) + y​

Answer 1

The digit at units place is y

Sum of digits is 11

So the digit at tens place will be = 11 - y

Therefore, the two digit number is -

10 ( 11 - y) + y

The correct answer is option (4)

Answer 2

Answer:

4,10(11-y) + y

Step-by-step explanation:

let the two digits be x&y

x+y =11

x=11-y

the two digit number be 10x+y= 10(11-y)+y