Question

The sum of the digits of a two-digit number is 11. If we interchange the digits then the
new number formed is 45 less than the original. Find the original number

Answer 1

Let Us Say the Two Numbers are

x and y

So, According to the Question

$x + y = 11..(1)$

and

$10y + x = 10x + y - 45..(2)$

which is Further

$= > 9x - 9y = 45$

$= > x - y = 5..(3)$

Now We will add Equation (1) and (3)

$x + y + x - y = 11 + 5$

$= > 2x = 16$

$= > x = \frac{16}{2} = 8$

Substituting The value of x in equation (1)

$= > 8 + y = 11$

$= > y = 11 - 8 = 3$

So,

• The Original Number = 83
• Reverse Number= 38

we Know that the Reverse Number is 45 less than the Original Number

To check, we will Subtract the numbers

i.e, 83-38= 45 (checked)

Answer 2

Answer:

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sorry for the inconvenience, 83-38=45(not128-45=83)