Question

the sum of the digits of a two digit number is 11 the digit at ones place to2 more than twice digit at tens place. find the number​

Answer 1

Let the digits be x and y and the number is 10x+y

Then x+y=11 and,

y= 2x+2

Substituting the value of y =2x+2

We get,

x+2x+2=11

3x+2=11

3x=11-2

3x=9

x=9/3

=3

and,

y=2×3+2

=6+2

=8

Thus the number is 10x×3+8=38