Question

The sum of the digits of a two-digit number is 11. The given number is less than the number obtained by interchanging the digits by 9. Find the number. The answer should be in one variable, not x and y, please.

Answer 1

Answer:

let the number is XY.

Then X+Y=11................... (i)

A.T.Q

10X+Y=(10Y+X)-9

10X+Y=10Y+X-9

10X-X+Y-10Y=-9

9X-9Y=-9

9 (X-Y)=-9

X-Y=-9/9

X-Y=-1 .............................. (ii)

adding both equation, we get..

X+Y=11

- ( X-Y)=-1

_________

2Y=12  

Y=12/2

Y=6

Put the value of Y in equation (i)

X+Y=11

X+6=11  

X=11-6

X=5

Hence the number is XY=56  

Step-by-step explanation:

hope it helps

plz mark as brainliest answer

sorry if wrong and thanks if right

Answer 2

Answer:

hi

Step-by-step explanation:

hi guys.

u tube par dekho rimorav vlogs