the sum of the digits of a two digit number is 11. the given number is less than the number obtained by interchanging the digits by 9. find the number.
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Hey
Here is your answer,
Two digit number: xy= 10x+y.
Sum of digits: x+y=11
xy is less then yx by 9: xy+9=yx
xy+9=yx
10x+y=10y+x-9
9x-9y=-9
x-y=-1,
So this is the system of equations to be solved:
x + y=11
x - y =-1
x=5, y=6
The number is 56.
Hope it helps you!
Here is your answer,
Two digit number: xy= 10x+y.
Sum of digits: x+y=11
xy is less then yx by 9: xy+9=yx
xy+9=yx
10x+y=10y+x-9
9x-9y=-9
x-y=-1,
So this is the system of equations to be solved:
x + y=11
x - y =-1
x=5, y=6
The number is 56.
Hope it helps you!
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