Question

The sum of the digits of a two digit number is 11. When we interchange the digits, it is
found that the resulting new number is greater than the original number by 63. Find
the two digit number.
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Answer 1

Step-by-step explanation:

Let the no. be 10x+y

given:- x+y =11.

condition 10y+x=10x+y+63

-9x+9y=63

from equation 1 and 2 we get

x+y=11×9

-9x+9y=63

we get 9x+9y=99

-9x+9y=63

18y=162

y=9

putting the value of y in equation 1 we get x=2 hence the required two digit no. is 10×2+9=29

Answer 2

Step-by-step explanation:

Let the no. be 10x+y

given:- x+y =11.

condition 10y+x=10x+y+63

-9x+9y=63

from equation 1 and 2 we get

x+y=11×9

-9x+9y=63

we get 9x+9y=99

-9x+9y=63

18y=162

y=9

putting the value of y in equation 1 we get x=2 hence the required two digit no. is 10×2+9=29