The sum of the digits of a two-digit number is 12. If the digits are reversed, the new number
is 12 less than twice the original number. Find the original number.
Answers
Answer:
The system of equations is as follows:
x+y=12
(10x+y)-(10y+x) = 18
From here, there are any number of possible ways to solve this system. I'll use the subtraction method, but first let's simplify equation 2:
x+y=12
9x-9y = 18
multiply both sides of equation one by 9
9x+9y=108
9x-9y=18
subtract equation two from equation one:
18y = 90
divide by 18:
y = 5
use the original first equation to find x now that we know y:
x + 5 = 12
x = 7
Now let's check that 75 actually answers the question:
5+7 = 12
75-57 = 18
So the original number is 75!
hope it's helpful for you
Step-by-step explanation:
sarthak2614356p8m3pj
20.05.2018
Math
Secondary School
+5 pts
Answered
The sum of 2 digit number is 12.If the digits are reversed,the new number is 12 less than twice the original number.Find the number
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Jades23
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x is the number in tenth place and y os the number in ones place
webew7 and 52 more users found this answer helpful
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SerenaBochenek
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Answer:
The number is 48
Step-by-step explanation:
Given that the sum of 2 digit number is 12. If the digits are reversed, the new number is 12 less than twice the original number.
we have to find the two digit number.
Let the two-digit number is xy therefore the number becomes 10x+y
As the sum of 2 digit number is 12 that means
x+y=12 → (1)
Now, if the digits are reversed, the new number is 12 less than twice the original number.
→ (2)
Solving (1) and (2), we get
(2)+8(1) ⇒
x+y=12 ⇒ 4+y=12 ⇒ y=8
Hence, the number is xy=48