Question

the sum of the digits of a two-digit number is 12 if the number formed by reversing the digit is greater than the original number by 54 find the original number

Answer 1

let the no be=10x+y----------(1)
sum of digits=12
>x+y=12-------(2)
no. formed by reversing the digits=10y+x---(3)
given that (3)=(1)+54
10y+x=10x+y+54
10x-x+y-10y=-54
9x-9y=-54
x-y=-54/9
x-y=-6-------(4)
(2)+(4)=>2x=6
x=3 sub. in (2) we get y=12-3=9
so from (1) required no.=10(3)+9=39.
hope it'll help
mark it as brainliest