The sum of the digits of a two digit number is 12. If the number formed by reversing its digits is greater than the original number by 18, find the original number
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Answer: I don't know
explanation: i have same doubt
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The number is 10x+y
Reversed number - 10y+x
According to the problem,
10x+y+18 = 10y+x
9x+18 = 9y
9(12-y) + 18 = 9y
108 - 9y + 18 = 9y
126 = 18y
y= 7
x+y = 12
x= 12 - 7 = 5
The original number - (10×5)+7 = 57
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