Question

The sum of the digits of a two digit number is 12. If the number formed by reversing its digits is greater than the original number by 18, find the original number

Answer 1

Answer: I don't know

explanation: i  have same doubt

Answer 2

The number is 10x+y

Reversed number - 10y+x

According to the problem,

10x+y+18 = 10y+x

9x+18 = 9y

9(12-y) + 18 = 9y

108 - 9y + 18 = 9y

126 = 18y

y= 7

x+y = 12

x= 12 - 7 = 5

The original number - (10×5)+7 = 57