Question

the sum of the digits of a two digit number is 12 if the new number formed by reversing the digits is greater than the original number by 54 find the original number and check your answer​

Answer 1

Let the number be = 10x + y

x + y = 12 ..... Equation 1

10y + x = 10x + y + 54

9y - 9x = 54

y - x = 6 ...... Equation 2

From Eqn 1 & 2,

y = 9

x = 3

So, the number is 39

Answer 2

Answer:

39

Step-by-step explanation:

Let the digit at the ten's place be x.

Given : The sum the digits of two digit number is 12.

→ the digit at the unit's place = 12 - x

→ Original number = 10x +(12 - x) = 9x + 12

If the new number formed by reversing the digits is greater than the original number by 54.

[10(12 - x) + x]- [10x +(12 - x)] = 54

After solving, we get

x = 3

Therefore original number = 9x + 12 = 9 × 3 + 12 = 39