Question

the sum of the digits of a two digit number is 12. if the new number formed by reversing the digits is greater than the original number by 18. find the original number. check your solution.​

Answer 1

Step-by-step explanation:

Let the one's digit digit be x and tens digit be y.

Given, x + y = 12 ----»»» equation 1

Original number = 10x + y

Reversed number = 10y + x

According to question,

10x + y + 18= 10y + x

9x - 9y = -18

9(x - y) = -18

x - y = -2 ---»»» equation 2

From adding eq.1 and 2, we get,

2x = 10

x = 5

From equation 1,

x + y = 12

y = 7

Original number = 10x + y

= 57