Question

the sum of the digits of a two-digit number is 12. if the new number formed by reversing digit is greater than the original number by 54,Find the original number .​

Answer 1

Answer:

39

Step-by-step explanation:

let the number in tens place is x

let the number in unit place is y

sum of the digits is x + y = 12 equ (1)

the number will be 10x + y

by reversing it becomes 10y + x

10x + y + 54 = 10y + x

10x + y - (10y + x) = - 54

10x + y - 10y - x = -54

9x - 9y = -54

9(x - y) = -54

x - y = -54/9

x - y = -6 equ (2)

adding (1) & (2)

2x = 6

x = 6/2 = 3

number in tens place is 3

number in unit place y

x + y = 12

3 + y = 12

y = 12 - 3

y = 9

the required number is 10x + y

= 10(3) + 9

= 30 + 9

= 39

hope you get your answer