the sum of the digits of a two digit number is 12.if the new number formed by reversing the digits is greater than the original number by 18, find the original number .check your solution And the options are 55 53 59 57....pls answer fast .....I will mark thefirst and correct answer as brainliest.
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Answered by
2
Answer:
- When the digits of a two digit number are reversed, the resulting number is 54 less than the original number. The tens digit of the original number 4 times the units digits.
Step-by-step explanation:
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Answered by
1
Answer:
the number is 57
Step-by-step explanation:
let the two digit number be 10y + x
according to question
x + y = 12
y = 12 - x --- equation 1
and
10x + y = 10y + x + 18
=9x-9y-18 = 0
substituting the value of y with x from equation 1
9x-9(12-x)-18 = 0
9x - 108 + 9x - 18 = 0
18x - 126 = 0
18x = 126
x = 126/18
x = 7
we know that x+y = 12
7+y = 12
y = 12-7
y = 5
we know that the number is 10y+x = (10*5)+7
=50+7
=57
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