Question

the sum of the digits of a two digit number is 12. if the new number formed by reversing the digit is greater than the original number by 54. find the original number. check your solution. (Ans ×=-1)





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Answer 1

Answer:

The alkaline earth metals are six chemical elements in group 2 of the periodic table. They are beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra).

Step-by-step explanation:

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Answer 2

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Explanation:

Given :

the sum of the digits of a two digit number is 12. if the new number formed by reversing the digit is greater than the original number by 54.

To Find :

Original number

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Let the ten's place digit be 'y' and unit digit be 'x'

Then number formed :$\bold{10y+x}$(original number )

Number formed after reversing the digit is $\bold{10x+y}$

According to the question:

Sum of two digits is 12 e.g=>$\bold{x+y=12}$

new number formed which is $\bold{10x+y}$ is less than its original number by 54

then our equation becomes :

$10x + y = 10y + x - 54$

$= > 10x - x + y - 10y = - 54$

$= > 9x - 9y = - 54$

$= > 9(x - y) = - 54$

$x - y = - 6.........(1)$

second equation is x+y=12 ........(2)

Solving equations 1 and 2 by adding both

$\bold{x-y+x+y=-6+12}$

$\bold{x{\cancel{-y}}+x+{\cancel{y}}=-6+12}$

$2x = 6$

$\bold{\red{\boxed{x = 3}}}$

now put X's value in equation 1

$x - y = - 6$

$3 - y = - 6$

$- y = - 6 - 3$

$- y = - 9$

$\bold{\red{\boxed{y = 9}}}$

We get$\bold{\red{ x=3 }}$and $\bold{\red{y=9}}$

Original number =10y+x =10×9+3=$\bold{\red{93}}$

number after reversing it =10x+y=10×3+9=$\bold{\red{39}}$