The sum of the digits of a two digit number is
12. If the new number formed by reversing the
digits is greater than the original number by 54,
find the original number.
Answers
Answered by
53
❒ Let the two digits be x and y respectively. The number is (10x + y). After, reversing the digits obtained number is (10y + x).
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- The sum of the digits of two digit number is 12.
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Now,
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Therefore,
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Answered by
220
hello
quesion ⤵️
The sum of the digits of a two digit number is
12. If the new number formed by reversing the
digits is greater than the original number by 54,
find the original number.
given↙️
two digit number is12
new number formed by reversing the
digits is greater than the original number by 54,
to. find
find the original number.
answer
39.
solusion ⬇️
according to. question
Let the digits be x and y, so the number will be = (10x+y), on reversing the digits, the new number will be = (10y+x)
According to the question we can write as x + y=12 and also we can write as 10y+x-10x-y=54
Which implies 9y-9x=54
y-x=54/9
y-x=6
y=6+x
Now on substituting this in x + y=12 we get
x+6+x=12
2x+6=12
2x=12-6
x=6/2=3
Now y=6+x=6+3=9
So the number is 39
To check: digit sum=3+9=12
Reversing the digit numbers becomes 93 and 93-39=54
Hence verified.
hope. it's. helps. you
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