Math, asked by madhu203, 1 year ago


The sum of the digits of a two-digit number is 12. If the new number formed by reversing the digits is greater than the original number by 54, find the original number. Check your solution.

Answers

Answered by srinjoy7
9
let the two digits be x and y
and also let's take x>y
original no = 10x+ y
atq,x+y=12 (1)
reversed no= 10y+x
atq, (10y+x)-(10x+y)=54
=>-x+ y =6 (2) on further reducing
now adding eq (1) and and eq (2) we get
y= 9
substituting y value in eq (1) or (2)
we get x=3
hence original number= (10x + y)=30+9= 39
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