The sum of the digits of a two-digit number is 12. If the new number formed by reversing the digits is greater than the original number by 18, find the original number. Check your solution.
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let the unit digit be x
So tens digit =12-x
number = 10 (12-x)+x=120 -9x
according to the question
10x+12-x -18=120 -9x
9x-6=120 -9x
9x+9x=120+6
18x=126
x=7
number =120-9x=120-9×7
=120-63
=57
So tens digit =12-x
number = 10 (12-x)+x=120 -9x
according to the question
10x+12-x -18=120 -9x
9x-6=120 -9x
9x+9x=120+6
18x=126
x=7
number =120-9x=120-9×7
=120-63
=57
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