Question

The sum of the digits of a two-digit number is 12. The difference of the digits is 6. Find the number ?

Answer 1

Let the number be x and y...

A.T.Q,

x + y = 12 ___(i)
x - y = 6 ____(ii)

Adding (i) and (ii)
x+y+x-y = 12+6
2x = 18
x = 9

Putting value together in eq.(i) , we get
x+y = 12
9+y = 12
y = 3

Proof...

x + y = 12
9 + 3 = 12
12 = 12

x - y = 6
9 - 3 = 6
6 = 6

Answer 2

The number is 93

Step-by-step explanation:

Let ten's place digit be x and unit's place be y

Number = 10x+y

The sum of the digits of a two-digit number is 12

x+y=12 -------1

The difference of the digits is 6

x-y=6   -------2

So, Add 1 and 2

2x=12+6

2x=18

x=9

Substitute the values in 1

9+y=12

y=3

Number = 10x+y=10(9)+3=93

Hence The number is 93

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