The sum of the digits of a two digit number is 12. The digit at units place is 3 more than twice the digit at tens place
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let the first digit be x
and the second digit be y
sum of them=12
therefore x+y=12_______result 1
Now, the digit at unit place is 3 more than the twice the digit at tens place
y=2x+3____ result 2
put y=2x+3 in x+y=12
x+(2x +3)= 12
3x = 12-3
x= 9/3
x=3
put x=3 in x+y=12
3+y=12
y=12-3
y=9
your two digit number is 39
Answered by
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Answer: 39
9= 2x+3
x= 3
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