Question

the sum of the digits of a two digit number is 12. the number obtained by interchanging the two digits exceeds the given number by 18. find the number.​

Answer 1

Answer:

x =5 and y=7

Step-by-step explanation:

Let the team's digit of the required number be x and the unit's digit be y. Then,

x+y=12. .....(1)

Required number =(10x+y)

Number obtained on reversing the digits =(10y+x)

--> (10y+x)- (10y+x)=18

9y - 9x =18

y-x=2. ......(2)

On adding (1) &(2) ,we get

2y=14 => y=7

Putting y=7 in (1),we get

x+7=12

x= 12 -7 =5

therefore, x=5 and y=7

Hence the required number is 57.