Question

The sum of the digits of a two digit number is

12. The number obtained by interchanging the two

digits exceeds the given number by 18. Find the

number.

Answer 1

let the digit in one place be x and digit in ten place be y

10x+y
reversing the digit =10y+x

y+x=12 ________1

10x+y=10y+x=18

10 X +y - 10 Y - X = 18
18(x-y)=18
x-y=1-______________2
adding equation 1 and 2
y=13/2
putting Y in equation 1
x+13/2=12
2x+13=12×2
2x=11/2


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