the sum of the digits of a two digit number is 12 the number obtained by reversing the digit is 36 greater then original number. find the number
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Step-by-step explanation:
The sum of the digit of the two digit number is 12. When the digit are interchange, the result number is 36 more than the original number. What is the original number?
Let the unit digit=X
Tens digit=12-X
The number=10(12-X)+X
The number after reversal=10(X)+12-X
The equation
10(12-X)+X-36 =10X+12-X
120–10X+X-36=10X+12-X
-10X+X-10X+X=12–120–36
-18X=-144
18X=144
X=144/18
X=8x
X=unit digit=8
Tens digit=12–8=4
The number=10(4)+8=48
Reverse number=84
84 is 36 more than 48
So the desired number is 48
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