Question

the sum of the digits of a two digit number is 12. the number obtained by interchanging the two digits exceeds the given number by 18. find the number.​

Answer 1

Answer:

Step-by-step explanation:

Let the tens digit of the required number be x and the units digit be y. Then,

x+y=12 .........(1)

Required Number = (10x+y).

Number obtained on reversing the digits = (10y+x).

Therefore,

(10y+x)−(10x+y)=18

9y−9x=18

y−x=2 ..........(2)

On adding (1) and (2), we get,

2y=14⟹y=7

Therefore,

x=5

Hence, the required number is 57.