The sum of the digits of a two – digit number is 12. The number obtained by interchanging its digit exceeds
the given number by 18.Find the number.
Answers
Answered by
9
Let the tens digit of the required number be x and the units digit be y. Then,
x+y=12 .........(1)
Required Number = (10x+y).
Number obtained on reversing the digits = (10y+x).
Therefore,
(10y+x)−(10x+y)=18
9y−9x=18
y−x=2 ..........(2)
On adding (1) and (2), we get,
2y=14⟹y=7
Therefore,
x=5
Hence, the required number is.
Answered by
6
Answer:
Let the tens digit of the required number be x and the units digit be y. Then,
x + y = 12............(1)
Required Number = (10x+y).
Number obtained on reversing the digits = (10y+x).
Therefore,
(10y+x)−(10x+y)=18
9y−9x=18
y−x=2 ..........(2)
On adding (1) and (2), we get,
2y=14⟹y=7
Therefore,
x=5
Hence, the required number is 57.
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