Question

the sum of the digits of a two digit number is 13 if the number obtained by reversing the digits is 45 more than the original number find the original number​

Answer 1

Answer:

one digit is 4 and another digit is 9

Step-by-step explanation:

The number is ab=10a+b=x

10b+a=x+y

And there should be a solution

Subtracting both equations

9(b−a)=y

a+b=n

a=n−b

9(b−a)=9(b−(n−b))=9(2b−n)=y

Or b=y+9n18

a=n−y+9n18  

Now y=45, n=13 then b=9 a=4

49+45=94

Answer 2

☆ Question ☆

The sum of the digits of a two digit number is 13 if the number obtained by reversing the digits is 45 more than the original number find the original number.

☆ Solution ☆

☆ Given ☆

• The sum of the digits of a two-digit number is 13 if the number obtained by reversing the digits is 45 more than the original number.

☆ To Find ☆

• The original number.

☆ Step-by-Step-Explaination ☆

Let two number be x and y .

Case 1 :-

x + y = 13 ------- 1

Case 2 :-

Let ten place digit number be 10x + y

After reversing 10x + y

So,

10x + y = 10y + x - 45

9x - 9y + 45

9 ( x - y + 5 ) = 0

x - y = -5 ----------------- 2

from ( 1 ) ( 2 )

x + y = 13 x - y = -5 / 2x = 8

x = 4

Putting in equation (2)

x - y = -5

4 - y = -5

- y = -5 - 4

y = 9

Number = 10x + y

10 × 4 + 9