Question

the sum of the digits of a two-digit number is 13 if the number obtained by reversing the digits is 45 more than the original number find position and by using a and b

Answer 1

Let the tens digit be a
& units digit be b

AT(I) condition
a + b = 13

AT (II) Condition
10b + a = 10a + b + 45
9b - 9a = 45
b - a = 5

a + b = 13
-a + b = 5
------------------
2b = 18
b = 9

Putting the value of b in equation 1
a + 9 = 13
a = 13 - 9 = 4

So, the no. will be 49.

Answer 2

Answer:

let the tens digit be a and units digit be b

AT (1) condition

a+b = 13

AT(2) Condition

10b + a = 10a + b = 45

9b - 9a = 45

b - a = 5

a + b = 13

a + b = 5

---------------

2b = 18

b = 9

putting the value of b in equation 1

a + 9 = 13

a = 13 - 9 = 4

so, the no. will be 49