The sum of the digits of a two digit number is 13. The number obtained by interchanging the digits exceeds the given number by 9. Find the number
Answers
Answered by
12
let the digit of ten's place be x and ones' place be y
x+y =13
(10y+x)-(10x+y)=9
9y-9x=9
-9x+9y=9
9(-x+y)=9
-x+y=1
from the two equations
2y=14
y=7
x+y=13
x=13-7=6
the number is 67
x+y =13
(10y+x)-(10x+y)=9
9y-9x=9
-9x+9y=9
9(-x+y)=9
-x+y=1
from the two equations
2y=14
y=7
x+y=13
x=13-7=6
the number is 67
Similar questions