Question

The sum of the digits of a two digit number is 13. The number obtained by interchanging the digits of the given number exceeds that number by 27. Find the number. Answer in x and y instead of a and b

Answer 1

Answer:

58

Step-by-step explanation:

Let the tens place digit be a

And unit place digit be b

According to first condition,

a + b = 13 -----(1)

According to second condition,

(10b+ a) - (10a + b) = 27

=> 10b + a - 10a - b = 27

=> 9b - 9a = 27

=> b - a = 3 ------(2)

On adding equation 1 and 2, we get

2b = 16

=> b = 8

Now,

On substituting the value of b in equation 1, we get

a + 8 = 13

=> a = 5

Number = 58

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