The sum of the digits of a two- digit number is 13. The number obtained by interchanging it's digits exceeds the given number by 27. Find the original number.
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Given:
- We have been given a number such that sum of its digits is 13
- The number obtained by interchanging its digit exceed the number by 27
To Find:
- We have to find the original number
Concept Used:
This Question can be solved by using the concept of linear equation in two variables which can be further solved by using any of the following technique
- Substitution
- Elimination
- Cross Multiplication
Solution:
Let the unit digit be = y
And Tens digit = x
When the digits are interchanged
According to first Condition :
Sum of digits of number is 13
---------------------------(1)
According to second Condition
The number obtained by interchanging its digit exceed the number by 27
Putting value of x from equation (1)
Putting value of y in Equation (1)
_______________________________
Original Number :
Original Number = 58
________________________________
________________________________
Sum of digits of number is 13
➡️Sum = 5 + 8
➡️Sum = 13
The number obtained by interchanging its digit exceed the number by 27
- Original Number = 58
- Reversed Number = 85
➡️Difference = 85 - 58
➡️Difference = 27
Hence Verified ...... ✍️
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