Math, asked by vijayupadhyay8218807, 11 months ago

The sum of the digits of a two- digit number is 13. The number obtained by interchanging it's digits exceeds the given number by 27. Find the original number.​

Answers

Answered by Anonymous
2

\huge\mathfrak\blue{Answer:}

Given:

  • We have been given a number such that sum of its digits is 13
  • The number obtained by interchanging its digit exceed the number by 27

To Find:

  • We have to find the original number

Concept Used:

This Question can be solved by using the concept of linear equation in two variables which can be further solved by using any of the following technique

  • Substitution
  • Elimination
  • Cross Multiplication

Solution:

Let the unit digit be = y

And Tens digit = x

\boxed{\sf{Original \: Number = 10x + y}}

When the digits are interchanged

\boxed{\sf{Reversed \: Number = 10y + x}}

\sf{  }

\odot \:According to first Condition :

Sum of digits of number is 13

\implies \sf{x + y = 13}

\implies \boxed{\sf{x = 13 - y}} ---------------------------(1)

\sf{ }

\odot \:According to second Condition

The number obtained by interchanging its digit exceed the number by 27

\implies \boxed{\sf{Reversed - Original = 27}}

\implies \sf{(10y + x) - (10x + y) = 27}

\implies \sf{10y + x - 10x - y= 27}

\implies \sf{9y - 9x = 27}

\implies \sf{y - x = 3 }

Putting value of x from equation (1)

\implies \sf{y - (13-y) = 3 }

\implies \sf{y - 13 + y = 3 }

\implies \sf{2y = 3 + 13}

\implies \sf{y = \dfrac{16}{2}}

\implies \boxed{\sf{y = 8 }}

\sf{ }

Putting value of y in Equation (1)

\implies \sf{x = 13 - 8}

\implies \boxed{\sf{x = 5}}

_______________________________

\odot \:Original Number :

\implies \sf{10 \times 5 + 8}

\implies \sf{50 + 8}

\implies \sf{58}

Original Number = 58

________________________________

\huge\underline{\sf{\red{A}\orange{n}\green{s}\pink{w}\blue{e}\purple{r}}}

\large\boxed{\sf{Original \: Number = 58}}

________________________________

\huge\mathtt\green{Verification:}

Sum of digits of number is 13

➡️Sum = 5 + 8

➡️Sum = 13

The number obtained by interchanging its digit exceed the number by 27

  • Original Number = 58
  • Reversed Number = 85

➡️Difference = 85 - 58

➡️Difference = 27

Hence Verified ...... ✍️

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