Question

The sum of the digits of a two digit number is 13. The number formed by interchanging the digits is 45 more then the original number. Find the original number.

Answer 1

let, the two digit no. be 10x +y

ATQ, x + y =13------------(1)

after interchange no. will be 10y+x

ATQ, 10y + x +45 = 10x +y

9y -9x = -45

y-x = -45

x-y = 45 -----------(2)

comparing both equations :

y = -16

x = 29

hence, original no. = 10(29)+(-16)

= 290 -16

= 274

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Answer 2

Answer:

274 is the correct answer plz follow me