Math, asked by seema9472kumari, 4 months ago

The sum of the digits of a two digit number is 13.The number obtained by interchanging the digits exceed the original number by 9 . Find the number.​

Answers

Answered by simran7539
7

Solution

Given :-

  • The sum of the digits of a two digit number is 13 .
  • The number obtained by interchanging the digits exceed the original number by 9 .

To Find :-

  • The number.

Step-by-Step-Explaination :-

Let the tens place be x and unit place be y

x + y = 13 ...........eq ( 1 )

Original number = 10x + y

By intercganging the digits = 10y + x

( 10x + y ) - ( 10y + x ) = 9

10y + x - 10x + y = 9

10y - y - 10x - x = 9

9y - 9x = 9

9 ( y - x ) = 9

y - x = 1

( 13 - x ) - x = 1 .....using eq ( 1 )

13 - 2x = 1

2x = 12

x = 12/2

x = 6

y = 13 - 6

y = 7

Hence,

The number is 67

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