The sum of the digits of a two digit number is 13.The number obtained by interchanging the digits exceed the original number by 9 . Find the number.
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☆ Solution ☆
Given :-
- The sum of the digits of a two digit number is 13 .
- The number obtained by interchanging the digits exceed the original number by 9 .
To Find :-
- The number.
Step-by-Step-Explaination :-
Let the tens place be x and unit place be y
x + y = 13 ...........eq ( 1 )
Original number = 10x + y
By intercganging the digits = 10y + x
( 10x + y ) - ( 10y + x ) = 9
10y + x - 10x + y = 9
10y - y - 10x - x = 9
9y - 9x = 9
9 ( y - x ) = 9
y - x = 1
( 13 - x ) - x = 1 .....using eq ( 1 )
13 - 2x = 1
2x = 12
x = 12/2
x = 6
y = 13 - 6
y = 7
Hence,
The number is 67
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