Question

The sum of the digits of a two-digit number is 13. The number obtained by interchanging its digits exceeds the given number by 9. Find the original number.​

Answer 1

Answer:

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Number =y×10+x

x+y=13⇒y=13−x

Interchange digits.

x×10+y= Number +9

x×10+13−x=(13−x)×10+x+9

10x+13−x−130+10x−x−9=0

18x=126

x=7

y=6

Number =60+7=67

Answer 2

Answer:

number =y×10+x

x+y=13⇒y=13−x

Interchange digits.

x×10+y= Number +9

x×10+13−x=(13−x)×10+x+9

10x+13−x−130+10x−x−9=0

18x=126

x=7

y=6

Number =60+7=67

Step-by-step explanation:

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