The sum of the digits of a two digit number is 13.the number formed by interchanging the digits is 45 more than original number.find the original number
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one digit=x
another digit=13-x
original no=10x+13-x
10(13-x)+x=45+10x+13-x
130-10x+x=58+9x
x=72/18=4
original no.=49
another digit=13-x
original no=10x+13-x
10(13-x)+x=45+10x+13-x
130-10x+x=58+9x
x=72/18=4
original no.=49
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