Question

The sum of the digits of a two-digit number is 13 the number obtained by interchanging the digits of the given number exceed that number by 45 find the number graphically

Answer 1

Answer :-

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Let us consider that the two digits are a and b.

Then the number is (10a + b).

When the digits are interchanged, the new number is (10b + a).

By the given condition :

a + b = 13 .....(i)

and

10b + a = (10a + b) + 45

=> 9b = 9a + 45

=> b = a + 5 .....(ii)

Putting b = a + 5 in (i), we get :

a + a + 5 = 13

=> 2a = 8

=> a = 4

From (ii), putting a = 4, we get :

b = 4 + 5 = 9

Therefore, the number is

= ( 10a + b )

= 10 × 4 + 9

= 40 + 9

= 49 [ • Required answer ]

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Thanks!

Answer 2

Answer:

x= 4 and y= 9

Step-by-step explanation:

Let the tens place be x and ones place be y

So the number is in the form of

10x + y

ATQ,

your answer from here is now attached below

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Therefore the number = 49

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