The sum of the digits of a two digit number is 13 .When the digits are interchanged, the new number so formed is 9 more than the original number. Find the original number.
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Answer:
Let one's digit = x
And, ten's digit = y
Therefore, number is 10y+x.
According to the question,
x+y=9 ....(1)
Also,
10y+x+9=10x+y
x−y=3 ......(2)
Solving equation 1 & 2, we get,
x=6 and y=3.
Hence, the original number is 10y+x=36
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