The sum of the digits of a two-digit number is 14. The number formed by reversing the digits is 36 less than the original number. Find the original number.
Answers
Answer:-
Let the number be (10x + y).
Given:
Sum of the digits = 14
→ x + y = 14
→ x = 14 - y -- equation (1).
And,
The number formed by reversing the digits 36 less than the original number.
→ 10x + y - 36 = 10y + x
Substitute x value from equation (1).
→ 10(14 - y) + y - 36 = 10y + 14 - y
→ 140 - 10y + y - 36 = 9y + 14
→ - 9y - 9y = 14 + 36 - 140
→ - 18y = - 90
→ y = - 90/ - 18
→ y = 5
Substitute y value in equation (1)
→ x = 14 - y
→ x = 14 - 5
→ x = 9
The number = 10(9) + 5 = 95.
Hence, the number is 95.
✬ Original Number = 95 ✬
Step-by-step explanation:
Given:
- Sum of the digits of a two digit number is 14.
- Number formed by reversing digits is 36 less than original number.
To Find:
- What is the original number ?
Solution: Let the unit and tens digit of number be y and x respectively. Therefore,
➟ x + y = 14 or
➟ x = (14 – y)........(1)
So original number will be :-
➯ Original number = (10x + y)
After reversing digits the number formed is:-
➯ Reversed number = (10y + x)
A/q
- Reversed number is 36 less than original number.
(10x + y) = (10y + x) + 36
10x – x = 10y – y + 36
9x = 9y + 36
9(14 – y) = 9y + 36
126 – 9y = 9y + 36
126 – 36 = 9y + 9y
90 = 18y
90/18 = y
5 = y
So,
➭ Unit digit of number is y = 5
➭ Tens digit = x = (14–y) = 14–5 = 9
Hence, The original number is
➫ (10x + y)
➫ 10(9) + 5 = 95