Question

the sum of the digits of a two digit number is 15 if the number formed by reversing the digit is less than the original number by 27​

Answer 1

Answer:

let tens digit of the original number be x

so original number,

10(x) + (15-x) 

reversing digits

10(15-x) + x

=>[10(x) + (15-x)]-[10(15-x)+x] = 27

 10x + 15-x - 150+10x-x = 27

10x + 10x + 15 - 150 -x - x = 27

20x - 135 -2x = 27

18x - 135 = 27

18x = 27 + 135

18x = 162

x = 162/18

x = 9

original number = 10(x) + (15 - x)

                           = 10 * 9 + 15 -9

                           = 90 + 6 = 96