Question

The sum of the digits of a two-digit number is 15 if the number obtained by reversing the digit is less than the original number by 27 find the original number .

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

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$\green{\underline \bold{Given :}}$

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• Sum of digits of two digit number is 15.

• Number obtained by reversing the digits is 27 less than the original number.

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$\red{\underline \bold{To \: Find:}}$

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• The original number

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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Let tens digit of the original number be: x

Hence one's digit will be 15 - x

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$\underline{\bold{\texttt{So original number,}}}$

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⇛ 10(x) + (15-x) 

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$\underline{\bold{\texttt{Reversing digits mean }}}$

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⇛ 10(15-x) + x

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Therefore,

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⇛ [10(x) + (15 - x)]-[10(15 - x) + x] = 27

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⇛ 10x + 15 - x - 150 + 10x - x = 27

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⇛ 10x + 10x + 15 - 150 -x - x = 27

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⇛ 20x - 135 - 2x = 27

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⇛ 18x - 135 = 27

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⇛ 18x = 27 + 135

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⇛ 18x = 162

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⇛ x = 162/18

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⇛ x = 9

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original number = 10(x) + (15-x) 

                              = 10(9) + (15-9)

                              = 90+6

$\purple\longrightarrow$ $\sf 96$

Answer 2

Answer:

the answer is 96

Step-by-step explanation:

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