Question

the sum of the digits of a two-digit number is 15. if the number formed by reversing the digits is less than the original number by 27, find the numbers.​

Answer 1

Answer:

96

Step-by-step explanation:

The sum of the digits of two digits is 15. If the number formed by reversing the digits is less than the original number by 27, what is the number? 96 is the number. x = 9, so y = 15–9 = 6, and so the answer is 96.

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Answer 2

Given:

The sum of the digit of a two-digit number is 15. The number formed by reversing the digits is less than the original number by 27.

To find:

The number.

Solution:

The number is 96.

To answer this question, we will follow the following steps:

Let the digits of a two-digit number be x and y where x is at ten's place while y is at one's place.

So,

The original number is 10x + y.

Now,

According to the question,

$x + y = 15 \: \: (i)$

Also,

After reversing the digits,

The number becomes 10y + x

So, according to the question,

$10y + x = 10x + y - 27$

This can be written as

$9x - 9y = 27$

$x - y = 3 \: \: (ii)$

After adding (i) and (ii), we get,

$2x = 18$

$x = 9$

On putting the value of x in (i), we get

$y = 6$

Now,

Original number = 10x + y = 10(9) + 6 = 96

Hence, the original number is 96.