The sum of the digits of a two-digit number is 15. If the number formed by reversing the digits is less than the original number by 27, find the original number. Check your solution.
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Step-by-step explanation:
Let the original number be 10x+y
So, Sum of its digits = x+y = 15 ...... (1)
If the digits are interchanged then
New number = 10y+x
Acc. to the question,
(10x+y) -(10y+x) = 27
By solving it We will get
x-y=3 ...... (2)
Adding both eqtn. (1) and (2) ,
We get x= 9
Putting this value in (1) ,
we get y= 6
So the number will be 96 i.e., 10+y
Hope it helps you...
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