the sum of the digits of a two digit number is 15 if the number formed by reversing the digit is less than the original number by 27 find the original number
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Answered by
0
let tens digit of the original number be x
so original number,
10(x) + (15-x)
reversing digits mean
10(15-x) + x
therefore
[10(x) + (15-x)]-[10(15-x)+x] = 27
10x + 15-x - 150+10x-x = 27
10x + 10x + 15 - 150 -x - x = 27
20x - 135 -2x = 27
18x - 135 = 27
18x = 27 + 135
18x = 162
x = 162/18
x = 9
original number = 10(x) + (15-x)
= 10(9) + (15-9)
= 90+6
= 96
Hope it helps❤
Answered by
2
Let the unit's place = x
The ten's place = 15
By reversing the digits, we get
According to the question
- Hence, the original number 96.
Thank you!
@itzshivani
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