Question

the sum of the digits of a two digit number is 15 if the number formed by reversing digit is less then the original number by 27 find the original number

Answer 1

Let the original no: be→
10x+y

Now on reversing the Digits we get→
10y+x

According to the question.
x+y=15 →(1)

10y+x=10x+y-27

→9y-9x=-27
→y-x=-3
→x-y=3
→x=3+y → (2)


Equating (1) and (2)

(y+3)+y=15

→2y=15-3
→y=6

so →x=3+6=9


Hence the original No: is[10(9)+6]=96.