Question

The sum of the digits of a two digit number is 15. If the nu
than the original number by 27, find the original number.​

Answer 1

Answer:

Let number at tens place be = x

So number at ones place = 15–x

Original number :-

$10(x) + 1(15 - x) \\ = 10x + 15 - x \\ = 9x + 15$

Reversed number:-

x will come at ones place and (x-15) will come at tens place .

so,

$1(x) + 10(15 - x) \\ = x + 150 - 10x \\ = 150 - 9x$

A\Q

Reversed number is greater than original number by 27.

$(9x + 15) + 27 = 150 - 9x \\ =) 9x + 42 = 150 - 9x \\ = )9x + 9x = 150 - 42 \\ = )18x = 108 \\ = )x = \frac{108}{18 } \\ = )x = 6$

Original number :-

9x +15

=)(9 * 6) + 15

=)54 + 15

=)69