The sum of the digits of a two digit number is 15.The number obtained by reversing the order ofthe digits of the the given number exceeds the given number by 9.Find the number
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hii mate !!
Let the digit at ten's place be x and one's place be y
So , x + y = 15 -------(i), x + y - 15 = 0
Original Number , = 10x + y
Reversing = 10y + x
According to Question,
10x + y + 9 = 10y + x
9 = 9y - 9x
9 = 9(y - x)
y - x = 1------ (ii)
(i) + (ii) , gives
x + y + y - x = 1 + 15 = 16
2y = 16 , y = 8
Applying value of y in (ii)
y - x = 1 , 8 -x = 1 = x = 7
Number , 10x + y = 10*7 + 8 = 78
Ans: The given number is 78
hope it helps !!☺☺☺
Let the digit at ten's place be x and one's place be y
So , x + y = 15 -------(i), x + y - 15 = 0
Original Number , = 10x + y
Reversing = 10y + x
According to Question,
10x + y + 9 = 10y + x
9 = 9y - 9x
9 = 9(y - x)
y - x = 1------ (ii)
(i) + (ii) , gives
x + y + y - x = 1 + 15 = 16
2y = 16 , y = 8
Applying value of y in (ii)
y - x = 1 , 8 -x = 1 = x = 7
Number , 10x + y = 10*7 + 8 = 78
Ans: The given number is 78
hope it helps !!☺☺☺
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