The sum of the digits of a two-digit number is 15.
When the digits are interchanged, the new number
is greater than the original number by 9. What is the
original number?
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Answer:
Let the units digit be x and tens digit be y.
Then, x+y=15 ……….(i)
Given number: 10y+x
Interchanged digits: 10x+y
A.t.Q:-
⇒(10x+y)−(10y+x)=9
⇒10x+y−10y−x=9
⇒9x−9y=9
⇒x−y=1 ………(ii)
Solving (i) and (ii)
x=8, y=7
∴ Two digit number=78.
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