Question

the sum of the digits of a two-digit number is 17 and the difference between the digit is 1 what is the two-digit number

Answer 1

heya.....

Let the number be 10x+y

So we can write

x+y=17------------------------------Eq 1

Reverse of the number will be 10y+x

So we can write

(10x+y)−(10y+x)=9

or

9x−9y=9

or

9(x−y)=9

or

x−y=99

or

x−y=1-------------------Eq 2

Adding up the Eq 1 and Eq 2

we get

x+y+x−y=17+1

or

2x+0=18

or

2x=18

or

x=182

or

x=9

By plugging the value x=9 in the x+y=17

We get

9+y=17

or

y=17−9

or

y=8

Therefore the number is 98

tysm.#gozmit

Answer 2

HEYA! !
ANSWER - : ✔ ✔ OUR TWO DIGIT NUMBER WILL BE XY=98.

HOPE IT HELPS ✌