Question

The sum of the digits of a two digit number is 17. If the number formed by reversing the digits is less than the original number by 9, find the original number ​

Answer 1

Answer:

98

Step-by-step explanation:

The digits are x and y

x+y=17

And x is in the tens position with y at ones

Thus the original number is 10x+y

When digits are reversed it is 10y+x which is (10x+y-9)

10x+y-9=10y+x

10x-x+y-10y=9

9x-9y=9

Divide through by 9

x-y=1

Solve simultaneous equations (imma use substitution)

From the second equation,x=y+1

If x+y=17

(y+1)+y=17

2y+1=17

2y=17-1

2y=16

y=16/2

y=8

If x=y+1

x=8+1=9

Original number is 10x+y

10(9)+8

=98

Please mark as brainliest

Answer 2

98 is the answer I think