Question

The sum of the digits of a two digit number is 17 on reversing the digits the number formed is 9 more than the original number find the original number when the answer

Answer 1

digit at ten - x
unit-y
original number 10x+y
interchange 10y+x
x+y=17....1
10x+y+9=10y+x
9x-9y=-9
x-y= -1 ....2
divided both sides with 9
adding 1 and 2
x+y=17
x-y=-1
2x=16
x=8
put x=8 in 1
8+y=17
y=9
therefore the original number is 89.
hope this helps you
don't forget to do it brainleist.

Answer 2

let, the unit place no. is x
tens place is y
so, no. is obtained is 10y+x
first condition
x+y=17...........(1)
reversing no. then
unit place no. is y
tens place no. is x
so, no. is obtained 10x+y
2nd condition
10y+x+10=10x+y
10=10x-x+y-10y
10=9x-9y
9x-9y=10
x-y=10/9..........(2)
(1)+(2)
x=17+10/9
x=163/9
put in eq. in (2)
163/9-y=17
y=10/9
so , no. is obtained 10y+x
=10×10/9+163/9
=263/9
I'm not sure but it is right