Question

the sum of the digits of a two-digit number is 24 if the new number formed by reversing the digits is greater than the original number by 36 find the original number​

Answer 1

EXPLANATION.

• GIVEN

The sum of the digit of a two digit number

is = 24.

if the new number formed by reversing the

digit is greater than the original number = 36.

Find the original number.

According to the question,

Let the tens place = x

Let the unit place = y

original number = 10x + y

reversing number = 10y + x

sum of digit of a two digit number= 24

=> x + y = 24 .......(1)

if the new number formed by reversing the

digit is greater than the original number = 36.

=> 10y + x - ( 10x + y) = 36

=> 10y + x - 10x - y = 36

=> 9y - 9x = 36

=> y - x = 4 ....(2)

From equation (1) and (2) we get,

=> 2y = 28

=> y = 14

put the value of y = 13 in equation (1)

we get,

=> x + 14 = 24

=> x = 10

Therefore,

original number = 10x + y

=> 10 X 10 + 14 = 114

Answer 2

I Thought This question is wrong.

Because Sum Of Two Digits can never Be 24

I'm seeing this after solving the question.

So SORRY.

Let :

• Unit Digit = y
• Tens Digit = x

Number : (10x + y)

x + y = 24 ... ( i )

New Number's :

• Unit Digit = x
• Tens Digit = y

New Number = (10y + x)

According to Question :

(10y + x) – (10x + y) = 36

10y + x – 10x –y = 36

9y – 9x = 36

– x + y = 4 .... ( ii )

Add ( i ) and ( ii )

We get,

2y = 28

y = 14

Putting The Value Of y in ( i )

x + y = 24

x + 14 = 24

x = 10

Hence, Number = (10x + y) = (10×10 + 14) = 114

Number = 114